解决获取作者 URL 错误

master
LiaoYijun 11 months ago
parent 1713ee15ab
commit 9261f05f85

@ -2652,10 +2652,11 @@ class Information extends CI_Controller
$data['ads_by_google'] = $ads_by_google;
$data['author'] = ''; //获取作者信息
$author = $this->Operator_model->get_author_nikename($information->ic_author);
$author_url = '';
if (!empty($author)) {
$data['author'] = $author->OPI_FirstName;
$data['OPI_Code'] = $author->OPI_Code;
$data['author_url'] = $this->get_author_url('www.japanhighlights.com', $author->OPI_Code);
$author_url = $this->get_author_url('www.japanhighlights.com', $author->OPI_Code);
} else {
$author_web = $this->Infoauthors_model->detail_by_id($information->ic_author); //原始作者,可能是在线作者等
if (!empty($author_web)) {
@ -2668,7 +2669,7 @@ class Information extends CI_Controller
// 结构化标签Article
$article_structured_data_content = $this->load->view(
$template_path . '-structured-data-article',
array('information' => $information, 'author_name' => $data['author'], 'author_url' => $data['author_url']),
array('information' => $information, 'author_name' => $data['author'], 'author_url' => $author_url),
true
);
$template = str_replace('<!--@STRUCTURED-DATA-ARTICLE-BLOCK@-->', $article_structured_data_content, $template);

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